20c^2+13cv-15v^2=

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Solution for 20c^2+13cv-15v^2= equation: 


Simplifying
20c2 + 13cv + -15v2 = 0

Reorder the terms:
13cv + 20c2 + -15v2 = 0

Solving
13cv + 20c2 + -15v2 = 0

Solving for variable 'c'.

Factor a trinomial.
(5c + -3v)(4c + 5v) = 0


Subproblem 1
Set the factor '(5c + -3v)' equal to zero and attempt to solve:

Simplifying
5c + -3v = 0

Solving
5c + -3v = 0

Move all terms containing c to the left, all other terms to the right.

Add '3v' to each side of the equation.
5c + -3v + 3v = 0 + 3v

Combine like terms: -3v + 3v = 0
5c + 0 = 0 + 3v
5c = 0 + 3v
Remove the zero:
5c = 3v

Divide each side by '5'.
c = 0.6v

Simplifying
c = 0.6v

Subproblem 2
Set the factor '(4c + 5v)' equal to zero and attempt to solve:

Simplifying
4c + 5v = 0

Solving
4c + 5v = 0

Move all terms containing c to the left, all other terms to the right.

Add '-5v' to each side of the equation.
4c + 5v + -5v = 0 + -5v

Combine like terms: 5v + -5v = 0
4c + 0 = 0 + -5v
4c = 0 + -5v
Remove the zero:
4c = -5v

Divide each side by '4'.
c = -1.25v

Simplifying
c = -1.25v
Solution
c = {0.6v, -1.25v}

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